🚪 Air Curtain Aerodynamics
Determine air curtain Foster Deflection Number (Dn), AMCA 220 aerodynamic sealing efficiency, doorway infiltration reduction, and heating/cooling energy saved.
⚡ Fortran 90 Engine
Double Precision (IEEE 754)
✓ ISO / ASME Validated
📊 Solver Telemetry
● ACTIVE
👁️ Consultations
43
⚡ Calculs faits
34
💾 Téléchargements
211
📦 Code Fortran
4.4 KB
📅 Mise en service
Jun 2026
⏱️ Latence
< 1 ms
🚪 Overhead Air Curtain Planar Jet Barrier & Deflection
Real-time visual simulation of downward turbulent jet resisting outdoor thermal & wind infiltration📝 Configuration & Presets
🛒 Supermarket (H=2.8m, 11.5 m/s)
❄️ Cold Storage (-20°C / +20°C)
🚛 Loading Dock (H=4.5m, 20 m/s)
🛍️ Retail Quiet (8.5 m/s)
AMCA 220 Formulations:
• Deflection Number: Dn = (ρi b₀ v₀² cos α) / [ g H² |ρo − ρi| + ½ Cp ρo vw² H ]
• Sealing Efficiency: Eseal ≈ 70% to 85% in optimal range (0.15 ≤ Dn ≤ 0.40)
• Thermal Energy Saved: Qsaved = Eseal · ṁinfilt · cp · |Ti − To| [kW]
• Deflection Number: Dn = (ρi b₀ v₀² cos α) / [ g H² |ρo − ρi| + ½ Cp ρo vw² H ]
• Sealing Efficiency: Eseal ≈ 70% to 85% in optimal range (0.15 ≤ Dn ≤ 0.40)
• Thermal Energy Saved: Qsaved = Eseal · ṁinfilt · cp · |Ti − To| [kW]
📊 Air Curtain Performance Results
Configure inputs and click Compute to view results.
📘 Calculation Methodology & AMCA 220 Standards
Foster Deflection Criterion
The Deflection Number $D_n$ compares the downward planar jet momentum against the opposing transverse forces of thermal buoyancy and wind pressure:
Dn = (ρi b₀ v₀² cos α) / [ g H² Δρ + ½ Cp ρo vw² H ]
Optimal Barrier Operation
When $0.15 \le D_n \le 0.40$, the air curtain reaches the floor with sufficient momentum to split cleanly, preventing up to 85% of conditioned air loss.
Key Engineering Assumptions
- Standard planar turbulent turbulent jet expansion angle $\approx 14^\circ$.
- Fan combined motor and aerodynamic efficiency $\eta = 60\%$.
- Outward nozzle discharge angle $\alpha = 15^\circ$ to counteract inward draft.