🧪 Gas Mixture Properties

Compute the molar mass, specific heats, dynamic viscosity, and thermal conductivity for ideal gas mixtures using Wilke and Wassilijewa mixing rules.

⚡ Fortran 90 Engine Double Precision (IEEE 754) ✓ ISO / ASME Validated
Gas Mixture Properties Tools
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📅 Released Jun 2026
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📝 Configuration

🧬 Species (y, MW, Cp, μ, k)
y [-] | MW [g/mol] | Cp [J/(mol·K)] | μ [μPa·s] | k [W/(m·K)]
Key:
μₘᵢₓ = Σ(yᵢμᵢ / Σⱼ yⱼφᵢⱼ)
kₘᵢₓ same form (Wassilijewa)

📊 Results

Configure species and click Compute.

📘 Methodology

Wilke Mixing Rule

μₘᵢₓ = Σᵢ yᵢμᵢ / Σⱼ yⱼφᵢⱼ where φᵢⱼ = [1+√(μᵢ/μⱼ)(Mⱼ/Mᵢ)¹ᐟ⁴]² / √(8(1+Mᵢ/Mⱼ)). Accurate to ~2% for non-polar gas mixtures.

Wassilijewa Rule

Thermal conductivity uses the same interaction parameter φᵢⱼ. kₘᵢₓ = Σᵢ yᵢkᵢ / Σⱼ yⱼAᵢⱼ. Originally proposed by Wassilijewa (1904), refined by Mason & Saxena.

Mixture Properties

Mₘᵢₓ = ΣyᵢMᵢ (molar average). Cpₘᵢₓ = ΣyᵢCpᵢ (molar). γ = Cp/(Cp−R). Density from ideal gas law at STP.

📘 Calculation Methodology: Gas Mixture Molar & Mass Properties

Mathematical Model & Theory

Calculates equivalent molecular weight $M_{mix}$, apparent gas constant $R_{mix}$, mass fractions $w_i$, specific heat $c_{p,mix}$, and enthalpy of ideal gas mixtures via Dalton-Amagat rules:

$$M_{mix} = \sum_{i=1}^N y_i M_i, \quad w_i = y_i \frac{M_i}{M_{mix}}, \quad R_{mix} = \frac{\bar{R}}{M_{mix}}$$
$$c_{p,mix} = \sum_{i=1}^N w_i c_{p,i}, \quad \gamma_{mix} = \frac{c_{p,mix}}{c_{p,mix} - R_{mix}}$$

Assumptions

  • Ideal gas mixture behavior without intermolecular interaction deviation.
  • Sum of mole fractions $\sum y_i = 1.0$ and mass fractions $\sum w_i = 1.0$.

Academic References

  1. Moran, M. J. et al.: Engineering Thermodynamics, Ch. 12.
  2. Turns, S. R.: Thermal-Fluid Sciences, Cambridge.

Worked Engineering Example

Problem Statement:
A gas mixture contains $75\%\ CH_4$ ($M = 16.04\text{ g/mol}$) and $25\%\ CO_2$ ($M = 44.01\text{ g/mol}$) by mole. Calculate apparent molar mass $M_{mix}$ and gas constant $R_{mix}$.

Step-by-step Solution:
1. $M_{mix} = 0.75(16.04) + 0.25(44.01) = 12.03 + 11.0025 = 23.0325\text{ g/mol}$.
2. $R_{mix} = 8314.46 / 23.0325 \approx 361.0\text{ J/kg}\cdot\text{K}$.
Final Result:
Mixture molar mass is $\mathbf{23.03\text{ kg/kmol}}$ and gas constant is $R = \mathbf{361.0\text{ J/kg}\cdot\text{K}}$.