๐ญ Regenerative Rankine Cycle
Analyze steam cycles with open or closed feedwater heaters. Compute extraction fractions and efficiency gains.
Thermodynamics
๐ Configuration
ฮทth = Wnet/Qin
Open FWH: yยทhext+(1โy)ยทhfw = hf,sat
BWR = Wpump/Wturbine
Wpump = vfฮP/ฮทp
๐ Results
Configure inputs and click Analyze to view results.
๐ Methodology
Regenerative Rankine
Extracting steam from the turbine to preheat feedwater raises average temperature of heat addition, improving thermal efficiency. Each extraction stage adds ~1โ3% efficiency gain.
Open vs Closed FWH
Open (direct contact) FWH mixes extracted steam with feedwater โ simple, effective, requires separate pump per stage. Closed (shell-tube) FWH keeps streams separate โ more complex but allows single pump.
Assumptions
- Simplified water saturation curve fits (educational).
- Isentropic efficiencies for turbine and pump.
- Saturated liquid exits each FWH.
- Steady-state, steady-flow.
๐ Calculation Methodology: Regenerative Rankine Cycle (Feedwater Heaters)
Mathematical Model & Theory
Regenerative feedwater heating extracts a fraction $y$ of expanding steam from the turbine to preheat boiler feedwater, raising the average heat addition temperature $\bar{T}_{in}$ and cycle efficiency:
Assumptions
- Open or closed feedwater heater at designated extraction pressure.
- Isentropic turbine stages.
Academic References
- Moran, M. J. et al.: Fundamentals of Engineering Thermodynamics, Ch. 8.
- Babcock & Wilcox: Steam: Its Generation and Use.
Worked Engineering Example
In a regenerative Rankine cycle, boiler inlet enthalpy is $h_1 = 3400\text{ kJ/kg}$, extraction steam is $h_b = 2800\text{ kJ/kg}$, condensate is $h_c = 190\text{ kJ/kg}$, and saturated liquid at extraction is $h_{fwh} = 760\text{ kJ/kg}$. Find extraction fraction $y$.
Step-by-step Solution:
1. Energy balance on Open FWH: $y h_b + (1-y) h_c = h_{fwh}$.
2. $y = (760 - 190) / (2800 - 190) = 570 / 2610 \approx 0.2184 = 21.84\%$.
Final Result:
Extraction bleed fraction is $y = \mathbf{21.8\%}$.