🥞 Plate Heat Exchanger
Chevron Plate Heat Exchanger (PHE) rating and sizing. Model enlargement factor, convection coefficients, and port/channel drops.
⚡ Fortran 90 Engine
Double Precision (IEEE 754)
✓ ISO / ASME Validated
Heat Transfer
📊 Solver Telemetry
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⚡ Solves
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📦 Fortran Code
4.1 KB
📅 Released
Jun 2026
⏱️ Latency
< 1 ms
PHE Design Parameters
Configure Chevron plates stack parameters and check flows or size the stack count:
- chevron Angle ($\beta$): Angle relative to vertical axis. Affects Nusselt and friction heavily.
- Pressing depth ($b$): Spacing between plates forming flow channels.
- Rating mode vs Sizing mode: Verify existing stack parameters or design the stack to fit target heat and pressure drop constraints.
📝 Configuration
📊 Results & Visualization
Configure parameters and click "Sizing Plate Heat Exchanger" to view channels stacks, temperature lines, and results.
📘 Calculation Methodology: Plate Heat Exchanger (PHE) Thermal & Hydraulic Sizing
Mathematical Model & Theory
Plate heat exchangers use corrugated chevron plates with angle $\beta$ to generate intense turbulence at low Reynolds numbers ($Re > 50$), maximizing Nusselt numbers while controlling pressure drops:
$$Nu = C \cdot Re^m Pr^{1/3} \left(\frac{\mu}{\mu_w}\right)^{0.14}, \quad \Delta p = 4 f \left(\frac{L}{D_h}\right) \frac{\rho V^2}{2} N_{pass}$$
$$D_h = \frac{2 b}{\Phi}, \quad q = U A \cdot LMTD \cdot F$$
Assumptions
- Equal channel mass flow distribution across parallel plates.
- Constant fluid properties at bulk mean temperature.
Academic References
- Kakac, S., Liu, H., & Pramuanjaroenkij, A.: Heat Exchangers: Selection, Rating, and Thermal Design, CRC Press.
- Shah, R. K., & Sekulic, D. P.: Fundamentals of Heat Exchanger Design, Wiley.
Worked Engineering Example
Problem Statement:
A PHE with 40 chevron plates transfers $q = 250\text{ kW}$ with $LMTD = 8.5^\circ\text{C}$, $F = 0.98$, and $U = 3500\text{ W/m}^2\cdot\text{K}$. Calculate required total plate heat transfer area $A$.
Step-by-step Solution:
1. Calculate effective temperature difference $\Delta T_{eff} = 8.5 \times 0.98 = 8.33^\circ\text{C}$.
2. Solve for area $A = q / (U \Delta T_{eff}) = 250,000 / (3500 \times 8.33) = 250,000 / 29,155 \approx 8.575\text{ m}^2$.
Final Result:
Required active plate surface area is $A = \mathbf{8.58\text{ m}^2}$ (approx. $0.22\text{ m}^2/\text{plate}$).
A PHE with 40 chevron plates transfers $q = 250\text{ kW}$ with $LMTD = 8.5^\circ\text{C}$, $F = 0.98$, and $U = 3500\text{ W/m}^2\cdot\text{K}$. Calculate required total plate heat transfer area $A$.
Step-by-step Solution:
1. Calculate effective temperature difference $\Delta T_{eff} = 8.5 \times 0.98 = 8.33^\circ\text{C}$.
2. Solve for area $A = q / (U \Delta T_{eff}) = 250,000 / (3500 \times 8.33) = 250,000 / 29,155 \approx 8.575\text{ m}^2$.
Final Result:
Required active plate surface area is $A = \mathbf{8.58\text{ m}^2}$ (approx. $0.22\text{ m}^2/\text{plate}$).