✈️ Standard Atmosphere Calculator (ISA 1976)
Determine U.S. Standard Atmosphere ($ISA$ 1976 / $ISO$ 2533) atmospheric properties at any geometric or pressure altitude. Supports temperature deviations, calculates density altitude, and tracks layers in real-time.
📋 Input Settings
🚀 Core Parameters
📊 Calculated Air Properties
| Property Name | Symbol | SI Metric Value | Imperial Value |
|---|---|---|---|
| Geometric Altitude | z | - | - |
| Geopotential Altitude | h | - | - |
| Temperature (Standard) | T_std | - | - |
| Temperature (Actual) | T | - | - |
| Atmospheric Pressure | P | - | - |
| Density of Air | ρ | - | - |
| Speed of Sound | a | - | - |
| Dynamic Viscosity | μ | - | - |
| Kinematic Viscosity | ν | - | - |
| Thermal Conductivity | k | - | - |
| Mean Free Path | λ | - | - |
| Local Gravity Acceleration | g | - | - |
| Pressure Altitude | z_p | - | - |
| Density Altitude | z_d | - | - |
| Pressure Ratio | δ | - | |
| Temperature Ratio | θ | - | |
| Density Ratio | σ | - | |
📘 Standard Atmosphere Mathematical Models
1. Geopotential Height & Gravity
The standard model integrates hydrostatic balance on a geopotential height $h$ to simplify the gravity variation $g(z)$ at geometric altitude $z$:
$$h = \frac{r_e \cdot z}{r_e + z}$$ $$g(z) = g_0 \cdot \left(\frac{r_e}{r_e + z}\right)^2$$Where the nominal Earth radius is $r_e = 6,356,766\text{ m}$, and gravity at sea level is $g_0 = 9.80665\text{ m/s}^2$.
2. Thermal Profile & Pressure
Within any atmospheric layer $b$ characterized by a constant temperature lapse rate $L_b = \frac{dT_{std}}{dh}$:
- If $L_b \neq 0$ (Linear lapse rate): $$T_{std} = T_b + L_b(h - h_b)$$ $$P = P_b \cdot \left[1 + \frac{L_b(h - h_b)}{T_b}\right]^{-\frac{g_0 M}{R^* L_b}}$$
- If $L_b = 0$ (Isothermal layer): $$T_{std} = T_b$$ $$P = P_b \cdot \exp\left[-\frac{g_0 M (h - h_b)}{R^* T_b}\right]$$
Where $M = 0.0289644\text{ kg/mol}$ is the molecular weight of air, and $R^* = 8.31432\text{ J/(mol K)}$ is the universal gas constant.
3. Transport & Kinetic Properties
Standard viscosity is governed by Sutherland's law, and thermal conductivity utilizes an empirical formulation:
$$\mu = 1.458 \times 10^{-6} \cdot \frac{T^{1.5}}{T + 110.4}$$ $$k = \frac{2.64638 \times 10^{-3} \cdot T^{1.5}}{T + 245.4 \times 10^{-12 / T}}$$The mean free path $\lambda$ (average distance traveled between molecular collisions) is computed based on effective collision diameter $d = 3.65\text{ Å}$:
$$\lambda = \frac{k_B T}{\sqrt{2} \pi d^2 P} \approx \frac{2.33228 \times 10^{-5} \cdot T}{P}$$